Sum of parallel routing

[ValentinC]

Hi, is there a fromula for estimate the total output level when adding parallel routings?

 

[Joe Bfstplk]

20×log(n), where n is the number of parallel rows of identical signal, gives the dB increase.

 

[dicXjonesify]

20×log(n), where n is the number of parallel rows of identical signal, gives the dB increase.

^That^
But as a quickie, combining 2 is ~6dB

 

[Rex]

^That^
But as a quickie, combining 2 is ~6dB

Combining two equal signals will give a 6 dB increase in level. Combining two uncorrelated signals of equal level will give a 3 dB increase.

 

[Greg Ferguson]

Somewhere ’round here there’s got to be a good thread from the past talking about the “additive properties of parallel routing”.

Also, it seems like the editor could do a decent job of setting the mix and level, based on the blocks in parallel, so we could click an “adjust for parallel use” button and it’d apply the formulas so we could adjust from there. But, then again it’s not that hard to figure out if we use our ears….

 

[ValentinC]

Thanks for the help, but it is not as simple as that.
I understand that Fractal splits the signal at equal levels when going parallel, i.e. if you exit the cab block at 0db and split the signal into 3 lines, those 3 lines start with 0dB signals.
The problem is that usually when you route in parallel, is for time effects, where you mix at 100% and get the level down, so each parallel line will have different signal levels before sum.

 

[mr_fender]

Yeah, it depends on the content of each parallel signal path, so there's not one formula that will work for all situations. It gets complicated quickly when you factor in the frequency, phase, and time aspects of each path's signal.

 

[Joe Bfstplk]

Yeah, it depends on the content of each parallel signal path, so there's not one formula that will work for all situations. It gets complicated quickly when you factor in the frequency, phase, and time aspects of each path's signal.

The formula above specifically calls out 'identical signals'.

It serves as a maximum boost amount for non-identical signals, so it is a decent boundary for focusing your search for the correct compensation amount....

 

[Greg Ferguson]

As they say here ‘bouts, “Parallel is haaaard!”